For the quantum number the =2, how many possible values are there for quantum number m subscript I? A. 2 B. 3 C. 5 D.6
The magnetic quantum number is ranging from the negative value of the azimuthal quantum number to the positive value.
So is that mean C?
C.
Hmmm nope.
Are you sure?Cuz i just looked it up and like 3 websites gave me that.
Lets look at it: \[\Large \sf principal ~ quantum ~ number = n\] \[\Large \sf Azimuthal~quantum~number=0... n-1=l\] \[\Large \sf magnetic~quantum~number=-l... +l=m\] Unless I count totally wrong and need to go to sleep: n=2 highest l = n-1 -> l=2-1 = 1 m = -1 , 0, +1
So Frostbite, what are you thinking answer wise?
Should be 3. The values l should be able to take should be -1, 0 and +1 we usually
Mind I see the web sides @Forever95 ?
Intresting.
yah
Frostbite, you sound like you know what you're doing.. So ill take your word for it.
its cool.lol
Did you notice it is for n = 3 on the webside? forever?
Thank you though @Forever95 :)
:P
nope.lol
blonde moment lol
@Forever95 I get plenty of those lol
But I'm glad you think I know what I'm doing since I work with quantum mechanics at the university I study at :P
yah im just a senior in high school....You would prob get a better chance with his awnser lol
"Just" is so negative. seniors in high school have lots of knowledge and they still surprise me. Anyway glad we got to a conclusion.
And welcome to \(\LARGE \sf \bbox[#40B9E9]{\color{white}{Open}}\bbox[#A8CE91]{\color{white}{Study}}\) @winston_salem !
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sorry had to lol
@Frostbite I'll let you know if you're correct! :)
I look forward to hearing I was correct ;)
But most important: did you understand how I got to the answer?
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