Question

Help me find the quotient and simplify?

m^2-n^2 m
--------- ÷ --------
m-n m^2-nm

So far I have it set up as "keep, change, flip". I can do this with numbers, it throws me off when there's only letters D:

Answer 1

\[\frac{m^2-n^2}{m-n}\times \frac{m^2-nm}{m}\] is a start

Answer 2

then factor a bunch
then cancel

Answer 3

"keep, change, flip"??!!

Answer 4

I have that. I combine them and I have (m^2-n^2)(m^2-nm)
------------------
(m-n)
for the top part would it be m^4-n^m ?

And yes, keep change flip. You keep the first section, change multiplication to division and flip the last section.

Answer 5

I'm just not sure if I'm combining correctly

Answer 6

letsf take it piece by piece:
m^2 - n^2 = (m - n)(m + n)
m^2 + mn + n^2 = (m + n)(m + n)
7m^2 = 7*m*m
nm^2 - mn^2 = nm(m - n)
now lets put it all together:

m^2 - n^2.............7m^2
--------------------- * -------------------- =
m^2+2mn +n^2....nm^2 - mn^2

(m-n)(m+n)............7m*m
---------------------* ---------------- =
(m+n)(m+n)........nm(m-n)

(m-n)*(m+n)*7*m*m
---------------------------------- =
(m+n)*(m+n)*n*m*(m-n)

lets divide out the (m-n)

(m+n)*7*m*m
------------------------- =
(m+n)*(m+n)*n*m

and then divide out the (m+n)

7*m*m
---------------- =
(m+n)*n*m

and last divide out m

7*m
------------ = answer
(m+n)*n

Answer 7

Awesome, thanks.

Answer 8

no problem

Answer 9

oh sorry Validavi Welcome to Open Study