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Mathematics 8 Online
OpenStudy (anonymous):

Hi, Im going to attach a pdf link file that contains the questions im unsure of working out. Its the Keystone Ohio program for algebra 2. I found help for the first 2 questions on here http://openstudy.com/study#/updates/4ffe732fe4b09082c06fa5d4 but I need help solving or if anyone wants to solve problems 3-6 http://curriculum.kcdistancelearning.com/courses/ALG2x-HS-A09/a/unit04/resources/docs/GraphingExponentialLogarithmicFunctionsAssignment.pdf i get probably no one wants to open the link cause I may be spreading a virus or something but really im need math help,so hope i get help

OpenStudy (anonymous):

i don't see 3 to 6 only 1 and 2

OpenStudy (anonymous):

ooh i see 3 now okay

OpenStudy (anonymous):

looks like it is up 2 units, so there will be a \(+2\) out at the end

OpenStudy (anonymous):

also i think it is shifted to the right 5 units, so you have \[2^{x-5}+2\] see if that works

OpenStudy (anonymous):

you see the point on the graph \((5,3)\) which says if \(x=3\) then \(f(x)=5\) since the graph is clearly shifted up by 2 units this tells you when you plug in 5 in to the exponent, you should get 1, and since \(2^0=1\) that means you are shifted to the right 5 units, i.e. it is \[2^{x-5}+2\] you can check that this works for the other points as well

OpenStudy (anonymous):

ok i said that completely wrong \[x=5,f(x)=3\] but the conclusion was correct sorry

OpenStudy (anonymous):

Thanks so much!

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