Question

2l ogx + logy - 3 logz

Answer 1

it would be log(x^2y/2z^3)

Answer 2

Accdg to the laws of logarithm
2logx = logx^2 3logz = logz^3
sum of 2 log is the log of its product:
log(x^2 y)- logz^3
difference of 2 log is the log of a quotient
therefore the simplified form is
log(x^2y)/logz^3

Answer 3

can you answer this 9^(x-1)=27

Answer 4

Good job!

Answer 5

We can use the logarithmic equations
(x-1) log 9 = log 27
x-1 = log 27/log9

Answer 6

you can continue from there

Answer 7

What would my answer be?

Answer 8

Oops the answer to the first question is log{(x^2y)/z^3}

Answer 9

are you allowed to use calculator to find the value of log 9 and log 27?

Answer 10

i am not sure, thanks for the help