Question

A container was pressurized with 150.0 kPa. What was the initial volume if the final volume is 20.4 L with a pressure of 40.0 kPa if there were no temperature change?
I'm pretty sure it's Boyle's Law
P1V1=P2V2

Answer 1

How do you solve for V1?

Answer 2

\(\Large P_1V_1=P_2V_2\)

\(\Large 150*V_1=40*20.4\)

\(\Large V_1=\dfrac{P_2V_2}{P_1}\)

\(\Large V_1=\dfrac{40*20.4}{150}\)

Answer 3

Thanks!