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Mathematics 14 Online
OpenStudy (anonymous):

HELP!!! show that the circle having the latus rectum of a parabola as diameter is tangent to the directrix.

OpenStudy (anonymous):

hello again

OpenStudy (anonymous):

hello!! yeheey :)

OpenStudy (anonymous):

lets put the parabola with vertex at the origin, and write its equation as \(x^2=4py\)

OpenStudy (anonymous):

therefore the length of the latus rectum is \(4p\) right?

OpenStudy (anonymous):

yesyes

OpenStudy (anonymous):

so if that is the diameter of the circle, then the radius of the circle is half of that, namely \(2p\)

OpenStudy (anonymous):

oh damn damn damn i screwed it up again jeez but it is close

OpenStudy (anonymous):

replace all the \(2p\) by just \(p\)

OpenStudy (anonymous):

it would be a lot easier if i could draw it let me try

OpenStudy (anonymous):

|dw:1377133791964:dw|

OpenStudy (anonymous):

the center of the circle is \((0,p)\) and the radius of the circle is \(2p\)

OpenStudy (anonymous):

from the center \((0,p)\) to the directrix \(y=-p\) is exactly \(2p\) units away, which is the radius of the circle so it must touch the directrix at the point \((0,-p)\)

OpenStudy (anonymous):

|dw:1377134040438:dw|

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