HELP!!! show that the circle having the latus rectum of a parabola as diameter is tangent to the directrix.
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
hello again
OpenStudy (anonymous):
hello!! yeheey :)
OpenStudy (anonymous):
lets put the parabola with vertex at the origin, and write its equation as \(x^2=4py\)
OpenStudy (anonymous):
therefore the length of the latus rectum is \(4p\) right?
OpenStudy (anonymous):
yesyes
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
so if that is the diameter of the circle, then the radius of the circle is half of that, namely \(2p\)
OpenStudy (anonymous):
oh damn damn damn i screwed it up again
jeez
but it is close
OpenStudy (anonymous):
replace all the \(2p\) by just \(p\)
OpenStudy (anonymous):
it would be a lot easier if i could draw it
let me try
OpenStudy (anonymous):
|dw:1377133791964:dw|
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
the center of the circle is \((0,p)\) and the radius of the circle is \(2p\)
OpenStudy (anonymous):
from the center \((0,p)\) to the directrix \(y=-p\) is exactly \(2p\) units away, which is the radius of the circle
so it must touch the directrix at the point \((0,-p)\)