Question

PLEASE HELP!

Under T, the point (0,2) gets mapped to (3,0). T -1 (x, y)

-(x + 3, y - 2)
-(x - 3, y + 2)
-(x - 3, y - 2)

AND

For the Transformation T, write the T-1.
T : (x, y) --> (x, y)
T -1: (x, y) --> ( , )

-(x, y)
-(x - 1, y - 1)
-(½x, ½y)

Answer 1

what does \(T-1\) mean?

Answer 2

is it maybe \(T^{-1}\) the inverse map?

Answer 3

YUP!

Answer 4

ok then maybe we can do this
also i hope those little - signs in front of the answers are not minus sings, just meaningless marks right?

Answer 5

lets do the second one first, because it is easiest
here \(T\) sends \((x,y)\) to \((x,y)\) in other words it doesn't do anything
it is the "identity map"
therefore going back also sends \((x,y)\) to \((x,y)\) so the inverse is also the identity map

Answer 6

in your notation the answer would be
\[T^{-1}:(x,y)\to (x,y)\]

Answer 7

ok ?

Answer 8

yes

Answer 9

now for the first one \(T\) sends \((0,2)\) to \((3,0)\) and so \(T^{-1}\) would send \((3,0)\) to \((0,2)\) right?

Answer 10

yupp

Answer 11

so it subtracts 3 from the first coordinate, and adds 2 to the second
which one is that?

Answer 12

you got it?