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Mathematics 20 Online
OpenStudy (anonymous):

trig identities

OpenStudy (anonymous):

\[secxtanx(1-\sin^2x)=?\]

OpenStudy (anonymous):

not sure how to approach this

OpenStudy (debbieg):

What is 1-sin^x =?

OpenStudy (anonymous):

\[1-\sin^2x=\cos^2x\]

OpenStudy (debbieg):

Well, yeah.... I wanted to see if she knew that.

OpenStudy (anonymous):

I did haha

OpenStudy (debbieg):

OK, so make that substitution, then put everything else in terms of sines and cosines.... I think you'll see it all fall into place! :)

OpenStudy (anonymous):

so you have to substitute everything into sine and cosine first in problems like these?

OpenStudy (anonymous):

Sorry, @DebbieG . Me, @Ariel.Chun , and @isabel_xxvi are all working on this together. We're all trying to solve the same problem.

OpenStudy (debbieg):

Well, it can be a good technique. It kind of depends on the ID, but it's going to work here.

OpenStudy (debbieg):

's ok @Dreweed :)

OpenStudy (debbieg):

so sec(x) = ? And tan(x)= ?

OpenStudy (anonymous):

sec x is 1/cosx

OpenStudy (anonymous):

tan x is sinx/cosx

OpenStudy (debbieg):

The main key here is, once you make that first Fundamental ID substitution, it's all just a product of trig functions. So the sines & cosines method is likely to work, because you'll see what can cancel out.

OpenStudy (debbieg):

Right... so what do you end up with after canceling where possible?

OpenStudy (anonymous):

sin x

OpenStudy (debbieg):

Excellent. :)

OpenStudy (anonymous):

yay!

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