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Mathematics 17 Online
OpenStudy (anonymous):

trig identities : check

OpenStudy (anonymous):

i believe this is false but im not sure

OpenStudy (anonymous):

Square both sides?

OpenStudy (anonymous):

is that allowed?

OpenStudy (anonymous):

i think it's false

OpenStudy (anonymous):

I think you get something like \[\cos^2 \frac{ a }{ 2 } = \frac{ 1-\cos(a) }{ 2 }\]

OpenStudy (anonymous):

thats what i did

OpenStudy (debbieg):

You either want to prove it's true, or find a counter example. Maybe try some easy values to see if you can get one that doesnt work?

OpenStudy (debbieg):

Try a=0

OpenStudy (anonymous):

Is the way I did it correct? By squaring both sides?

OpenStudy (anonymous):

for questions like this maybe its best to plug it in?

OpenStudy (debbieg):

Or a=pi

OpenStudy (anonymous):

so it's false

OpenStudy (debbieg):

Plugging in values will only work to DISprove an identity, e.g., show it's NOT an identity. That's fine as a way to disprove it. Just don't ever try it to PROVE it, there you must show that it works for ALL values of the variable so you have to show it algebraically. :)

OpenStudy (anonymous):

alright!

OpenStudy (debbieg):

Yup, it's false - you see that it doesn't work for a=0 or a=pi. If you've studied half-angle identities, you'll see that the RHS is actually =sin(a/2)

OpenStudy (anonymous):

ah i see thanks!

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