find all the points of the form (x,-x) which are 1 unit from the origin

Question

debbieg · Answer

well, that would be a portion of the circle that is centered at the origin and has a radius of 1. Do you know how to set up the equation for a circle?

anonymous · Answer

|dw:1377137012128:dw|

debbieg · Answer

Oh, wait.... I see... (x, -x). So you just want to points that are on the 45-degree line y=-x, and on the aforementioned circle.

debbieg · Answer

Since the points are of the form (x, -x), can you tell which quadrant(s) they will be in?

anonymous · Answer

distance formula is what we been doing? so $$d=\sqrt{(x _{2}-x _{1})^{2}+(y _{2}-y _{1)}^{^{2}}}$$

debbieg · Answer

|dw:1377137171885:dw|

Can just use the distance formula, with (x,-x) and (0,0) and set it =1.

anonymous · Answer

oh ok

debbieg · Answer

Haha... I was just typing to use the distance formula as you posted that. :)

anonymous · Answer

so do i set d=1 ?

anonymous · Answer

??

anonymous · Answer

i know to use distance formula just dont know how to set it up

anonymous · Answer

@DebbieG  ??

anonymous · Answer

@mathstudent55  could u help me ?

debbieg · Answer

Sorry, I was not near computer. Yes, set the distance=1, and use the points (x,-x) and (0,0)

debbieg · Answer

When you find one point, in the other point you'll just flip the negative and the positive coordinate.