Find the inverse laplace transform of 1/s^4.
@Loser66
ok so laplace transform of t^3 is 6/s^4 so in that fraction we are missing only the 6 so nothing would change in the fraction if we rewrite it as \[\frac{ 1 }{ 6 }\frac{ 6 }{ s^{4} }\] now find inverse laplace of that with pulling out of the inverse laplace the 1/6 since its a constant
But how did you get the t^3?
its table laplace transform laplace of t^n is : \[L(t^{n})=\frac{ n! }{ s^{n+1} }\] but here its inverse laplace so you are given the right side so you work backwards
So you get it from 4-1=3, t^3, right?
yes thats right
And how did you get that the laplace transform of t^3 is 6/s^4?
it is a table laplace transform , i was using the formula i wrote above
check in you table of laplace transforms you should have laplace transform of t^n
Okay, thanks.
ur welcome :)
Join our real-time social learning platform and learn together with your friends!