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OpenStudy (anonymous):
@Loser66
OpenStudy (anonymous):
ok so laplace transform of t^3 is 6/s^4
so in that fraction we are missing only the 6 so nothing would change in the fraction if we rewrite it as \[\frac{ 1 }{ 6 }\frac{ 6 }{ s^{4} }\]
now find inverse laplace of that with pulling out of the inverse laplace the 1/6 since its a constant
OpenStudy (anonymous):
But how did you get the t^3?
OpenStudy (anonymous):
its table laplace transform laplace of t^n is :
\[L(t^{n})=\frac{ n! }{ s^{n+1} }\]
but here its inverse laplace so you are given the right side so you work backwards
OpenStudy (anonymous):
So you get it from 4-1=3, t^3, right?
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OpenStudy (anonymous):
yes thats right
OpenStudy (anonymous):
And how did you get that the laplace transform of t^3 is 6/s^4?
OpenStudy (anonymous):
it is a table laplace transform , i was using the formula i wrote above
OpenStudy (anonymous):
check in you table of laplace transforms you should have laplace transform of t^n
OpenStudy (anonymous):
Okay, thanks.
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