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Mathematics 10 Online
OpenStudy (anonymous):

Factor completely: 18m^3 − 12m^2 + 6m

OpenStudy (anonymous):

6m (3m^2 − 2m + 1) 2m (9m^2 − 6m + 3) 6 (3m^3 − 2m2 + m) 6m (3m^2 − 2m)

OpenStudy (anonymous):

I know it is not B or C but do you get 1 after taking out the 6m?

OpenStudy (mathstudent55):

What factor do all terms have in common?

OpenStudy (anonymous):

so what do \[18m ^{3}-12m ^{2}+6m\] have in common

OpenStudy (anonymous):

6m, I solved it but when yuo factor it do you leave a 1 at the end or no?

OpenStudy (mathstudent55):

Good. When you factor out he 6m, you will have to have three terms inside the parentheses.

OpenStudy (mathstudent55):

Yes, you must leave the 1 at the m.

OpenStudy (anonymous):

Oh ok I see.

OpenStudy (mathstudent55):

Remember that factoring is the opposite of multiplying out.

OpenStudy (mathstudent55):

Look at this simple example. Factor: 9x^2 + 3x

OpenStudy (mathstudent55):

Here, the common factor is 3x, right?

OpenStudy (anonymous):

yupp because 9 has x^2

OpenStudy (mathstudent55):

Right. We factor out the 3x: Do we get 3x(3x) or 3x(3x + 1)?

OpenStudy (anonymous):

I guess 3x + 1 because you have to leave a placeholder basically right?

OpenStudy (mathstudent55):

All you need to do is multiply out our two possibilities. Whichever one gives you back what you started with is the correct answer.

OpenStudy (mathstudent55):

Let's do both multiplications: 3x(3x) = 9x^2 3x(3x + 1) = 9x^2 + 3x Since only the second choice gives us the original binomial back, the second choice is the correct factorization.

OpenStudy (anonymous):

Ah ok, so basically we leave it because 1 never really affects anyhing, like 2*1 = 2

OpenStudy (mathstudent55):

Correct. The 1 needs to be there to have something to multiply the factored out 3x to end up with 9x^2 + 3x.

OpenStudy (anonymous):

Ah I see, interesting concept :D you taught me plenty

OpenStudy (mathstudent55):

Right. Remember in our example, if you leave out the 1 in the factorization, you end up multiplying back together and ending up with only 9x^2, not the 9x^2 + 3x expression we started with.

OpenStudy (anonymous):

Yes because when you distribute it out in keeps 3x intact since it is only 1

OpenStudy (mathstudent55):

Right. What you need to remember is that factorization and multiplication are opposite operations. Factorization is undoing a multiplication. If you ever need to check if a factorization was done correctly, just multiply it out. You must end up with the original expression. If you don't the factorization is incorrect.

OpenStudy (anonymous):

Ah I see, wel thanks a bunch though really helped :)

OpenStudy (mathstudent55):

You're welcome.

OpenStudy (anonymous):

Now I know what OpenStudy is about :D

OpenStudy (mathstudent55):

Great. Keep asking questions.

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