convert r^2=4rsin tetha to cartesian
x^2+y^2=r^2 rsin(theta)=x
also identify the type of graph it will make....like is it a line or cirlce thx
What would you do. Do you see?
x² + y² = r² sin(theta) = y/r Take this equation --> r^2 = 4r sin(theta) and substitute for r² and sin(theta). @lilshadow
^ What he said. Same method as me.
rsin(theta)=y sorry. Typo.
@Dido525 Why do you say that the "4" is not relevant?
I mean like during the conversion.
Of course it's still going to be part of the final answer.
Maybe I should not have said that.
wait guys but i get x^2+y^2=4y. What kind of graph does that make?
Think about this in terms of Polar coordinates.
r=4sin(theta) .
In polar coordinates, y=sin(theta) is a circle.
That 4 stretches it by a factor of 4.
So in essence, you Have a circle of Radius 4.
That's my reasoning at least.
@lilshadow If you don't recognize the graph from its equation, sketch the graph here: http://www.wolframalpha.com/ Enter the equation in the search field.
@Dido525 Isn't the diameter 4 and the radius 2?
Yeah. Again. A silly mistake. Thanks :P .
The radius is 2 and the Diameter is 4.
Alrite thx guys!
We were happy to help.
Yeah no problem :) .
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