Question

algebra 2 question about functions. wait while I draw it

Answer 1

Do you mean \(f^{-1}(x)\)?

Answer 2

no

Answer 3

the problem has a positive 1.. is that weird?

Answer 4

i know how to do the first 2 steps

Answer 5

Yes, I'm not sure what that means. Someone yesterday posted the same kind of question. What have you covered in your class? Is this in a section on inverse functions??

Answer 6

no, function notation

Answer 7

there are a few inverse function questions too

Answer 8

Where did your y go, and where did your 7 come from?

Answer 9

i switched it

Answer 10

wait woops

Answer 11

its supposed to be 5x= y +12

Answer 12

you switch the x and the y variables

Answer 13

OK, I think this is asking for in inverse function. Not sure though why your problem would use the "1" instead of "-1", that isn't correct notation. But let's assume it's asking you to find an inverse.

Answer 14

ok

Answer 15

Right, you are finding an inverse so you switch x and y. Now you said the function was:

y=5x+12

So "switch the x and y" means to change the letter to y to x, and the letter x to y.

Answer 16

It does NOT mean to just swap the positions of the terms, follow me? (that's what you did)

Answer 17

ohhh

Answer 18

So what do you get when you SWITCH x for y and y for x?

Answer 19

so.. x= 5y+12?

Answer 20

Right! Now solve for y!

Answer 21

not sure how..

Answer 22

divide both sides by 5?

Answer 23

Once you do that, that is your inverse function, \(f^{-1}(x)\)

Answer 24

Not yet, what do you need to do first? Before you divide?

Answer 25

When working to solve an equation, always get all of the terms WITHOUT the variable on one side, and terms with the variable on the other, first. THEN you can divide to get the variable alone.

Answer 26

so.. x-5y = 12?

Answer 27

Dont move the 5y, move the 12. You are solving FOR y, so get the 5y term all alone.

Answer 28

5y= x-12

Answer 29

then divide by 5 on both sides

Answer 30

Yes!

Answer 31

y = x-12/ 5

Answer 32

Oops, careful.... if what you really mean is \[y=\frac{ x-12 }{5 }\]then perfect. But what YOU WROTE is \[y=x-\frac{ 12 }{5 }\]which is wrong.

Answer 33

thats what i mean

Answer 34

the first way

Answer 35

y = x-12 <-- this over 5

Answer 36

OK, then next time just make sure you use () if you don't want to mess with the equation editorl
y=(x-12)/5 would have been correct. :)

Answer 37

ok

Answer 38

Yes, you got it!