how do i graph y=3x^2+7x+2
What tools do you have? Algebra 1 - Plotting Points Algebra II/Analytic Geometry - Vertex Form of Parabola Calculus - Critical Points CAS - Get a computer to do it for you.
algebra 2
Perfect, then you'll need to complete the square on the right hand side.
y=3x^2+7x+2 I'll do it once for free if you're rusty.
i know that in the graph we have a x and a y intercept right
That's a good place to start. The y-intercept is easy. Just substitute x = 0 and get y = 2. Done! x-interecpts are a little harder, requiring factoring or the quadratic formula (or completing the square)
I prefer two more things before that, though. x is squared and y is linear. This gives a parabola that opens either up or down. The coefficient on x^2 is positive (3), so this one opens up! There, that makes me feel better.
There is also an easy way to find the axis of symmetry (a direct result of completing the square, actually.)
You are in very capable hands, stick with tkhunny and learn.
so how do i graph if the vertex is -7/6
So, you DO know the magic -b/(2a)! Just find the value of y associated with x = -7/6 With a vertex, 2 x-intercepts, a y-intercept, and some idea about symmetry you should be good to go!
but how do i graph it
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whats my next step
Where are all the points you had catalogued?
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