Question

Suppose ∠A and ∠B are complementary angles, m∠A = (3x + 5)°, and
m∠B = (2x – 15)°. Solve for x and then find m∠A and m∠B.

Answer 1

∠A and ∠B are complementary angles, so


m∠A + m∠B = 90

(3x+5)+(2x-15) = 90

solve for x

Answer 2

after you find x, you can plug it into the two equations to find m∠A and m∠B

Answer 3

i dont get it

Answer 4

are you able to solve (3x+5)+(2x-15) = 90 for x?

Answer 5

no i dont know how

Answer 6

(3x+5)+(2x-15) = 90

3x+5+2x-15 = 90

5x - 10 = 90

5x = 90+10

5x = 100

x = ??

Answer 7

16?

Answer 8

no
20

Answer 9

no, but close

Answer 10

sorry

Answer 11

yep x = 20

no worries

Answer 12

so if x = 20, then what is m∠A

Answer 13

i dont know i jsut learned this today and im so confused

Answer 14

its ok, since m∠A = 3x+5 and we know that x = 20, we can plug it in to get

m∠A = 3x + 5

m∠A = 3*20 + 5

m∠A = ??

Answer 15

65?

Answer 16

good

Answer 17

ok thank you so much

Answer 18

how about m∠B ?

Answer 19

you're welcome

Answer 20

wait how do we find m∠B?

Answer 21

m∠B = 2x - 15

x = 20

so...?

Answer 22

oh i see how you got that now i get how to find it it would be 25 i get it now

Answer 23

yep, so

x = 20
m∠A = 65
m∠B = 25

Answer 24

as a check, notice how m∠A and m∠B add to 90 degrees, that proves they are complementary

Answer 25

i need help with this too

Answer 26

go ahead and post a new question off to the left and tag me in it if you still need help

Answer 27

thank you