Question

(nRT^-2)^32/R^-2T^32 Is there an easier way to do this one?

Answer 1

i had n32r32/t96

Answer 2

but i think its wrong

Answer 3

\[\frac{ (nRT ^{-2})^{32} }{ R ^{-2}T ^{32} }\]?

Answer 4

that's correct

Answer 5

is it \[(nRT)^{-2}?\]

Answer 6

it's (nRT^-2)32/r^-2t^32 jen

Answer 7

Well, let's distribute that 32 power on top and see what exactly is going on:
\\[\frac{ n ^{32}R ^{32}T ^{-2*32} }{ R ^{-2}T ^{32} } \]
Now you can see that the 32 on top multiplies in to each power. So that T part on top I'll simplify:
\[\frac{ n ^{32}R ^{32}T ^{-64} }{ R ^{-2}T ^{32} } \]

Answer 8

So looks like you got one slight thing off. That should be R^34 on top.

Answer 9

psymon good i got that correct so i'm glad about that, but somewhere after i messed up again

Answer 10

Well, you have a R^-2 on bottom that gets moved up and added into the R^32 on top, combining to become R^34.

Answer 11

okay so i did what you said now my final answer looks like n^32r^34/t96 is this correct

Answer 12

Yep :3

Answer 13

okay i think i'm getting it finally thanks psymon

Answer 14

Thats good ^_^ Yeah, the exponent rules are really important in higher math, so good to understand them now.

Answer 15

yes