Question

help please!!

Answer 1

alright

Answer 2

find the x and y intercepts \[y=\sqrt{16-(x-2)^{2}}\]
i found the y intercept but need help finding x intercepts

Answer 3

put the thing inside the radical equal to zero and solve

Answer 4

ok yes i know that but thats where i am having difficulty!!

Answer 5

what do you guys call an intercept ? english not my native lang so... :/

Answer 6

\[16-(x-2)^2=0\]
\[16=(x-2)^2\] so
\[x-2=4\] or \[x-2=-4\]

Answer 7

@Alienium , an intercept is the point where curve crosses the axis