2y^2 - 5y -2 = 0

Question

2y^2 - 5y -2 = 0

lilsis76 · Answer

$$2y ^{2} - 5y -2 = 0$$

I divided by 2 to get.....$$y ^{2} - \frac{ 5 }{ 2 }y -1 = 0$$   did i do it right so far?

wolf1728 · Answer

Yes so far it's right but if you use the quadratic formula, you don't even have to divide the equation by 2.

lilsis76 · Answer

really? okay let me try it. give me a couple of min to figure it out and ill tag u back ya? :)

wolf1728 · Answer

Sure

anonymous · Answer

I would factor :P . But quadratic works too.

psymon · Answer

Id quadratic, lol.

lilsis76 · Answer

lol Can i see both? hold on  I tried sending it but openstudy lost connection give me a second.

lilsis76 · Answer

$$5\pm \sqrt{41}/4$$

psymon · Answer

I should do complete the square for the hell of it.

wolf1728 · Answer

But does that factor easily?  By that I mean does it factor into something unwieldly such as x-37/43 ?

psymon · Answer

You need the 5 to be divided by 4, too.

lilsis76 · Answer

complete the square? lol like....$$2y ^{2} -5y-5/2 = 2-5/2$$

anonymous · Answer

You forgot to square it :) .

anonymous · Answer

Quadratic is easier haha.

lilsis76 · Answer

if  i square it I would get 25/4  though

wolf1728 · Answer

lil sis I believe you have it right but don't forget the 5 gets divided by 2*a or 4 also

psymon · Answer

quadratic is easier, but complete the square would just be for the hell of it xD

lilsis76 · Answer

hmmm.... okay. Isnt that what I did? haha

anonymous · Answer

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