Question

factor the following sum of two cubes: m^3+64n^3

Answer 1

Use the identity : \(a^3 + b^3 = (a+b)(a^2-ab+b^2)\)
Can you first identify what are a and b respectively?

Answer 2

yeah, i know the format. i go it down to: (mn)^3+4^3

Answer 3

Nope....

64 = x^3
What is x?

Answer 4

4?

Answer 5

Yup. So, you get
\[m^3+64n^3\]\[=m^3+(4n)^3\]You can apply the identity right away.

Answer 6

is it: (m+4n)(m^2-4mn+4n^2)

Answer 7

Check the term "4n^2" again.

Answer 8

It should be(4n)^2, that is...

Answer 9

eh, i got it wrong. It was (m+4)(m^2-4mn+16n^2)