Mathematics
10 Online
OpenStudy (anonymous):
Solve for y.
y-2/y-6 = y+1/y-5+1
13 years ago
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OpenStudy (anonymous):
\[\frac{ y-2 }{ y-6 } =\frac{ y+1 }{ y-5+1 }\] ??
13 years ago
OpenStudy (nincompoop):
coocookakabird, how about you try to solve it
how do we know what you know if you're not even going to try and just wait for someone to feed you solutions
13 years ago
OpenStudy (anonymous):
I'm sorry but i didn't study math from 2 years i need to review it but today i have to finish something before
13 years ago
OpenStudy (anonymous):
I will try to solve it
13 years ago
OpenStudy (anonymous):
ok i 'll help u
13 years ago
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OpenStudy (anonymous):
Thanks my friend ^_^
13 years ago
OpenStudy (anonymous):
\[y-2divy-6=y +1divy -5 +1\]
13 years ago
OpenStudy (anonymous):
1 is not with y-5
13 years ago
OpenStudy (anonymous):
\[\frac{ y-2 }{ y-6 } =\frac{ y+1 }{ y-5 } +1 \] ??
13 years ago
OpenStudy (anonymous):
@kaka2266 is this right?
13 years ago
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OpenStudy (anonymous):
yup
13 years ago
OpenStudy (anonymous):
ok first u have to add 1 to \[\frac{ y+1 }{ y-5 }\]
13 years ago
OpenStudy (anonymous):
it already have 1 right
13 years ago
OpenStudy (anonymous):
it's
13 years ago
OpenStudy (anonymous):
i think y=7.5
13 years ago
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OpenStudy (anonymous):
did any one solve it?
13 years ago
OpenStudy (anonymous):
i think 7.5 is not correct
13 years ago
OpenStudy (anonymous):
Ammm
13 years ago
OpenStudy (anonymous):
i will try it again...did u find it?
13 years ago
OpenStudy (anonymous):
i know how to find it
13 years ago
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OpenStudy (anonymous):
Hhhhh how
13 years ago
OpenStudy (anonymous):
do u find \[\frac{ y+1 }{ y-5 } +1\] ?
13 years ago
OpenStudy (anonymous):
\[y + 1 \div y-5 + 1\div1\]
13 years ago
OpenStudy (anonymous):
right?
13 years ago
OpenStudy (anonymous):
\[\frac{ a }{ b } +\frac{ c }{ d }=\frac{ ad+bc }{ bd }\]
13 years ago
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OpenStudy (anonymous):
so it will be just y+1/y-5
13 years ago
OpenStudy (anonymous):
one moment
13 years ago
OpenStudy (anonymous):
y=1=y-5/y-5
13 years ago
OpenStudy (anonymous):
y+1+y-5/y-5
13 years ago
OpenStudy (anonymous):
\[\frac{ y+1 }{ y-5} +\frac{ 1 }{ 1 } =\frac{ (y+1) +(y-5)}{y-5 }\]
13 years ago
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OpenStudy (anonymous):
yup
13 years ago
OpenStudy (anonymous):
okay so y-2/y-6=(y=1)=(y-5)/y-5
13 years ago
OpenStudy (anonymous):
y-2/y-6+(y+1)+(y-5)/y-5
13 years ago
OpenStudy (anonymous):
how do u find that term?
13 years ago
OpenStudy (anonymous):
y-2/y-6=(y+1)+(y-5)/y-5 hate that
13 years ago
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OpenStudy (anonymous):
yes
13 years ago
OpenStudy (anonymous):
i think by taking term 2 into the other side?
13 years ago
OpenStudy (anonymous):
but u can simplify the right tem
13 years ago
OpenStudy (anonymous):
i know it will be 2y-4/y-5
13 years ago
OpenStudy (anonymous):
yes u r right
13 years ago
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OpenStudy (anonymous):
now i will take it to other side
13 years ago
OpenStudy (anonymous):
now u can use this method
\[\frac{ a }{ b }=\frac{ c }{ d }------>ad=bc\]
13 years ago
OpenStudy (anonymous):
ur method is right too
13 years ago
OpenStudy (anonymous):
1 min
13 years ago
OpenStudy (anonymous):
yaah i used urs
13 years ago
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OpenStudy (anonymous):
but that is complex
13 years ago
OpenStudy (anonymous):
good
13 years ago
OpenStudy (anonymous):
-y^2+9y-14=0 is that right
13 years ago
OpenStudy (anonymous):
yeah it is right
13 years ago
OpenStudy (anonymous):
(y+7)(y+2)?
13 years ago
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OpenStudy (anonymous):
no plz be careful,do it again
13 years ago
OpenStudy (anonymous):
this is ur equation....y^2-9y+14=0
13 years ago
OpenStudy (anonymous):
yup
13 years ago
OpenStudy (anonymous):
so (y-7)(y-2)
13 years ago
OpenStudy (anonymous):
y=7,2 right?
13 years ago
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OpenStudy (anonymous):
RIGHT
13 years ago
OpenStudy (anonymous):
^_^ thanks a lot for ur time man.
13 years ago
OpenStudy (anonymous):
u can examine ur answers
13 years ago
OpenStudy (anonymous):
NP
13 years ago
OpenStudy (anonymous):
Yup i will
13 years ago