Mathematics
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OpenStudy (anonymous):
Choose the correct simplification of 3 over x to the power of negative 7.
x to the 7th power over 3
3 over x to the 7th power
3x7
Already simplified.
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OpenStudy (skullpatrol):
Any ideas?
OpenStudy (skullpatrol):
$$\huge \frac{3}{x^{-7}}$$
OpenStudy (anonymous):
wht i dont get it?
OpenStudy (skullpatrol):
Is that the expression you want to simplify?
OpenStudy (anonymous):
I think so
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OpenStudy (skullpatrol):
You should make sure that you have the right question first, no?
OpenStudy (anonymous):
can u just help me with the solution
OpenStudy (skullpatrol):
yes, if you make sure you have the right question please :-)
OpenStudy (anonymous):
yes i think i know the right question
OpenStudy (skullpatrol):
OK, let's start with what a negative exponent means.
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OpenStudy (anonymous):
postive
OpenStudy (skullpatrol):
postive?
OpenStudy (anonymous):
7
OpenStudy (skullpatrol):
Yes.
OpenStudy (anonymous):
so what does it means
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OpenStudy (skullpatrol):
You said "7"
OpenStudy (skullpatrol):
I assume you know what you mean when you said it
OpenStudy (skullpatrol):
Maybe you just guessed at the answer?
OpenStudy (skullpatrol):
If you were guessing that the -7 becomes +7 then you are right.
OpenStudy (skullpatrol):
What did you base that guess on?
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OpenStudy (anonymous):
no the positive 7 i didn't guess it
OpenStudy (skullpatrol):
$$\huge\frac {3}{x^{-7}}=?$$
OpenStudy (skullpatrol):
I'm only here to help you learn, I can't learn for you.
OpenStudy (anonymous):
so it \[\frac{ 3 }{ x ^{7} }\]
OpenStudy (skullpatrol):
Nope. Try to use what you know about negative exponents...
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OpenStudy (skullpatrol):
$$\huge a^{-n}=\frac{1}{a^n}$$
OpenStudy (skullpatrol):
Have you seen this definition before?
OpenStudy (anonymous):
yes i think so
OpenStudy (skullpatrol):
Try to apply it to your question please.
OpenStudy (anonymous):
is it \[\frac{ x ^{7} }{ 3 }\]
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OpenStudy (skullpatrol):
$$\huge\frac {3}{x^{-7}}=\frac{3}{\frac{1}{x^7}}$$
OpenStudy (skullpatrol):
Do you see how I used the definition on $$x^{-7}$$in the denominator?
OpenStudy (anonymous):
so its already simplified.
OpenStudy (skullpatrol):
Nope.
OpenStudy (anonymous):
wait its \[3x ^{7}\]
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OpenStudy (skullpatrol):
Yes, by multiplying the numerator and the denominator by $$x^7$$ you get the simplification: $$3x^7$$
OpenStudy (anonymous):
so i was right
OpenStudy (anonymous):
so its c right just to make sure
OpenStudy (skullpatrol):
Yes.
OpenStudy (anonymous):
thank u
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OpenStudy (skullpatrol):
Thanks for trying to learn something new.
OpenStudy (anonymous):
okay