Question

Suppose that the functions p and q are defined as follows.

p(x)=2X + 2

q(x)=-2x^2

find

( q . p)(2)=

(p . q)(2)=

Answer 1

Could someone help me with it please?

Answer 2

The answer is

(q.p)(2)= -48

(p.q)(2)=-48
right?

Answer 3

yup,
\(\large f.g\) is multiplication of those 2 functions

Answer 4

and when you plug in x=2, you will get that answer.

Answer 5

i meant \(\large p.q\)

Answer 6

Yah but in the question there is a circle not a dot... is it the same?

Answer 7

it's like that (q O p)(2)

Answer 8

ohhh, this
\(\large (p \:o \:q)\)(2)
yes, it is diffferent!

Answer 9

yup it's like that

Answer 10

it is call composition of functions, read as q of p of 2 -->(q o p) (2)

Answer 11

first find p(2) what do you get ?

Answer 12

plug in x=2 in p(x)

Answer 13

6

Answer 14

q(x)=-8

Answer 15

correct!
so we have
\((q o p)(2)= q (p (2))\)
but p(2) = 6, so,
\((q o p)(2)= q (p (2))=q(6)\)
got this ?

Answer 16

so in the first one it will be like this -8(6)?

Answer 17

or just q(6)

Answer 18

nopes, to get q(6) we put x=6 in q(x)
what do u get ?

Answer 19

don't know yet hhhh

Answer 20

like you put x=2 in p(x) to get 2(2)+2 = 6
put x=6 in q(x) to get
-2(6^2) =... ?

Answer 21

ohhh now i see

Answer 22

1 min i will solve it

Answer 23

so the first one=-72

second=-14

right?

Answer 24

oh, wow! you learn fast :D
absolutely correct \(\huge \checkmark\)

Answer 25

Thanks a lot Hartnn u r great (:

Answer 26

lol, welcome ^_^