Question

Does anyone know how to do this ... D=KA[T2-T1/L] and solve for T1

Answer 1

\[\Large D=KA\left[\frac{T_2-T_1}{L}\right]\]

Answer 2

You need to bring everything without \(\large T_1\) to the other side.
That means THESE things:
\[\Large D=\color{red}{KA}\left[\frac{\color{red}{T_2-}T_1}{\color{red}L}\right]\]

Answer 3

Any idea how?

Answer 4

@Msbballshayla stay with me...

Answer 5

OH .. no I don't know how to .. I'm still lost at the T2 - T1 over L part

Answer 6

Chill... we're going to use operations on both sides... just remember
multiply and divide cancel out
add and subtract cancel out

Answer 7

So... the KA bit is multiplied, so how do we remove it?

Answer 8

Divide it on both sides

Answer 9

That's right.
\[\Large \frac{D}{\color{red}{KA}}=\frac{KA\left[\frac{T_2-T_1}{L}\right]}{\color{red}{KA}}\]

Answer 10

These cancel out:
\[\Large \frac{D}{\color{}{KA}}=\frac{\cancel{KA}\left[\frac{T_2-T_1}{L}\right]}{\cancel{\color{red}{KA}}}\]

Answer 11

Leaving...
\[\Large \frac{D}{KA}= \frac{T_2-T_1}{L}\]

Answer 12

Next step? :)

Answer 13

Let's get rid of the L.
How to do that?

Answer 14

Times L on both side of the equal sign

Answer 15

That's right... I don't see what's troubling you :)
\[\Large \color{red}L\times\frac{D}{KA}= \color{red}L\times\frac{T_2-T_1}{L}\]

Answer 16

\[\Large \frac{LD}{KA}= \cancel{L}\times \frac{T_2-T_1}{\cancel{L}}\]

Answer 17

It was how to get the T2 and T1 from being a fraction

Answer 18

That's already done... L cancels out, see? ^

Answer 19

Yes I see now.

Answer 20

You get \[\Large \frac{LD}{KA}= T_2-T_1\]
Can you do it now? :)

Answer 21

Do you subtract T2 from both sides now?

Answer 22

Yes, sure, that's possible :)
\[\Large \frac{LD}{KA}\color{red}{-T_2}= T_2-T_1 \color{red}{-T_2}\]

Answer 23

Simplified into:
\[\Large \frac{LD}{KA}-T_2= -T_1\]Finally?

Answer 24

I get it now .. but there is still problem similar to this one that still gets me.

Answer 25

Sure. Hit me.

Answer 26

Might want to post a new one though, to avoid lags.

Answer 27

Okay .. I'll see what problems I have left on my homework to get helped on.