Question

5x^2+5x 60=0

Answer 1

You missed a "+" sign?

Answer 2

What is between 5x and 60?

Answer 3

^

Answer 4

the problem does not have an = it is just a space

Answer 5

it says 60=0 is that -60=0?

Answer 6

it also says find all roots

Answer 7

\[5x^2+5x +60=0 \rightarrow 5(x^2+x +12)=0 \rightarrow x^2+x +12=0\]
\[x^2+x +12=0 \rightarrow x^2+x +12=0\]
Now use quadratic eq in order to find its roots

Answer 8

\[x^2+x+12=0 \] comparing it with \[ax^2+bx+c=0 \] we find
a=1, b= 1, c=12
\[x= \frac{-b \pm \sqrt{b^2-4ac}}{2a}\]
\[x= \frac{-1 \pm \sqrt{1^2-4 \times 1 \times12}}{2 \times 1}\]
\[= \frac{-1 \pm \sqrt{1-48}}{2 }= \frac{-1 \pm \sqrt{-47}}{2 }= \frac{-1 \pm i \sqrt{47}}{2 }\]
Therefore \[x=\frac{-1 +\ i \sqrt{47}}{2 } ---or ----x=\frac{-1 -\ i \sqrt{47}}{2 }\] are the required roots of the given quadratic equation

Answer 9

@johnmjku

Answer 10

so the 60=0 becomes +60 and those are all the roots of the equation?

Answer 11

@dpasingh