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OpenStudy (anonymous):
ABCD is a rectangle. find the length of each diagonal.
AC=2(5a+1)
BD=2(a+1)
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OpenStudy (anonymous):
I got 0
OpenStudy (anonymous):
Impossiple for a real rectangle
OpenStudy (anonymous):
|dw:1377279918091:dw|
OpenStudy (anonymous):
I assume it looks like that
OpenStudy (anonymous):
we know that
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OpenStudy (anonymous):
2(5s+1)=2(a+1)
OpenStudy (anonymous):
I also think you might have a typo
2(5s+1)=2(a+1)
^ ^
I think either both s or both a
OpenStudy (anonymous):
both a
OpenStudy (anonymous):
Either way if both s and a are the same you get 0 Put you plug it back in to either side of the equation
2(0+1)
0+1=1 I get 1
OpenStudy (anonymous):
You missunderstand G. a=0 :P but not the diagonals
the diagonals =
2(5a+1)
or
2(a+1)
plug in 0 at and you get
2(0+1)
0+1=1
or
2(5*0+1)
0+1=1
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OpenStudy (anonymous):
YOU MADE ME GET THE WRONG ANSWER
OpenStudy (anonymous):
what is right answer then?
OpenStudy (anonymous):
who knws im not on this problem any more hint its closed
OpenStudy (anonymous):
2(5*0+1)
0+2
2
i distributed wrong :(
It was 2 sorry
OpenStudy (anonymous):
OMG IM NOT ON THIS PROBLEM ANYMORE
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