Given F(x) shown below, complete the equation for the inverse of F(x). If necessary, use the slash mark (/) for the division symbol. F(x)=x-1 f^-1(y)=_______
y/1?
f(x) = x-1 y = x-1 ... replace f(x) with y x = y -1 ... swap x and y now solve for y
oh nvm about the swap, they just want you to solve y = x - 1 for x
okay so its not y/1 its x/1?
Right... weird notation, we saw this on another problem earlier.
You have y=x-1 What do you do to solve that for x?
you swap the numbers?
I'm not sure what you mean by that. could you be more specific? Or just show the result.
You either add, subtract, multiply or divide, {something} from both sides.
ok you add the -1 and you get y/2
hmmmm..... if you have y=x-1 How does adding 1 (which is what you mean: add 1, not add (-1)) to both sides get you y/2 anywhere?
y+??=x-1+??
y/0
well, y/0 would be undefined... but more importantly, I'm puzzled as to how/why you are getting that?
y=x-1 x=y-1 y=x+1
\(y=x-1\) \(y+1=x-1+1\) add one to both sides \(y+1=x\) simplify on right side, since -1 +1=0 There is no division involved, but you keep wanting to divide y by stuff. Can you tell me why? I'm just trying to get at where your confusion is coming from.
Well, yes.... that's how I would expect you to find the inverse. However, your teacher appears to want you to NOT swap x & y, but instead just solve the original equation for x. Which is a bit goofy, frankly. I would have done it the way YOU show above, getting y=x+1 as the inverse for y=x-1 That's really a notational matter though.
so my final answer is...
final answer is >.
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