Ask your own question, for FREE!
Mathematics 20 Online
OpenStudy (anonymous):

Solve the inequality 3(x + 1) + 2(x + 2) > 0. x < -7/5 x > -7/5 x < 7/5 x > 7/5 so far i got 3(x+1)+2(x+2)>0 to 3x+2x+4>0 is this correct ?

OpenStudy (abb0t):

No. You're missing a term.

OpenStudy (anonymous):

where

OpenStudy (abb0t):

\(3x+3+2x+4>0\)

OpenStudy (anonymous):

explain it further plz

OpenStudy (abb0t):

Combine like terms. If it helps, it is very similar to thinking of this as a function rather than an inequality, so you have \(3x+3+2x+4=0\). Now what do you do?

OpenStudy (anonymous):

so D

OpenStudy (abb0t):

Wrong!

OpenStudy (anonymous):

grr....do i switch this> to this<

OpenStudy (abb0t):

No. You're not dividing by a negative!

OpenStudy (anonymous):

well than how am i wrong can you explain form where you left off

OpenStudy (abb0t):

You get: \(5x+7>0\) correct? What's next? Subtract.....

OpenStudy (alienium):

5x > -7 x > -7/5

OpenStudy (anonymous):

so 5x>-7

OpenStudy (abb0t):

YES!

OpenStudy (anonymous):

then x >-7/5

OpenStudy (alienium):

solution space : ] -7/5 ; +infinite [

OpenStudy (abb0t):

Correct.

OpenStudy (anonymous):

thanks once again

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!