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Solve the inequality 3(x + 1) + 2(x + 2) > 0. x < -7/5 x > -7/5 x < 7/5 x > 7/5 so far i got 3(x+1)+2(x+2)>0 to 3x+2x+4>0 is this correct ?
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No. You're missing a term.
where
\(3x+3+2x+4>0\)
explain it further plz
Combine like terms. If it helps, it is very similar to thinking of this as a function rather than an inequality, so you have \(3x+3+2x+4=0\). Now what do you do?
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so D
Wrong!
grr....do i switch this> to this<
No. You're not dividing by a negative!
well than how am i wrong can you explain form where you left off
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You get: \(5x+7>0\) correct? What's next? Subtract.....
5x > -7 x > -7/5
so 5x>-7
YES!
then x >-7/5
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solution space : ] -7/5 ; +infinite [
Correct.
thanks once again
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