Find S8 for the series -2 + -10 + -50 + -250 +…
A third try? IF we are to assume that it is a Geometric Series, which the problem statement does NOT say, you can just add them up. Trivial a = a Boring a + ar = a(1+r) Now we're getting somewhere interesting! a + ar + ar^2 = a(1 + r + r^2) = \(a\cdot\dfrac{1 - r^{3}}{1-r}\) Generally a + ar + ar^2 + ... + r^{n-1} = a(1 + r + r^2 + ... + r^(n-1)) = \(a\cdot\dfrac{1 - r^{n}}{1-r}\) That's all it takes. Determine a = the 1st term r = the common ratio n = the desired sum rank and you are on your way.
this is no help.. thnks anyway
Seriously? You're not going to do ANY work? What's the first term? You must be able to do that.
Come on!! Tell me the first term. Look up at the series and read it off.
im kool... thnks again
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