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Mathematics 16 Online
OpenStudy (anonymous):

A table has 4 boys and 4 girls sitting around it. If the sitting is arranged at random find the probability that all boys sit together

OpenStudy (callisto):

Can you find the number of arrangements when all boys sit together?

OpenStudy (anonymous):

it would be 4!*5!

OpenStudy (callisto):

Right. What about the total number of arrangements of 8 people?

OpenStudy (anonymous):

its 7! because its (n-1)!?

OpenStudy (callisto):

No?! There are 8 people you have to arrange in order. So, for the first place, you can have 8 choices. For the second place, you can have 7 choices. For the third place, you can have 6 choices. . . . Then the total number of arrangement is...?

OpenStudy (anonymous):

8! ?

OpenStudy (callisto):

Yes. So, the probability required is the expected outcome (number of arrangements of 4 boys sitting together) / total number of arrangements.

OpenStudy (anonymous):

so it is 4!/8!?

OpenStudy (callisto):

No.

OpenStudy (callisto):

What is the expected outcome?

OpenStudy (anonymous):

there are 4! ways (for the boys to sit together) and there are 5! all together so 4!*5!?

OpenStudy (callisto):

Yes. Then, divide it by the total number of arrangements of 8 people.

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