please help! What is the equation of the line that passes through (-2, 2) and (1, -4)? -y = 2x - 2 -y = -2x - 4 -y = -2x - 2 -y = 2x + 4
First find slope Slope formula:\[\frac{ (y2-y1) }{ (x2-x1) }\]
thats the formula hahahaha correct :D
(-2,2) (1,-4) x1,y1 x2,y2 Plug in the values and solve @ttop0816
@jacalneaila @uri thank you so much!
ok sorry uri
lol @uri go easy on her And yes @ttop0816 that's just the slope... which is only the beginning :D
this is the guide @ttop0816
The website doesn't load @jacalneaila ^_^
oh.... haha please explain the rest please!
Gladly @ttop0816 But first, please find the slope of the line. I think it was briefly mentioned...
ah really
?why? lol XD
Hey @uri please be nice :(
@uri okay i found the slope
@uri -2
@uri be calm
Brilliant :) When you know the slope \(\large \color{blue}m\) of a line as well as a point \(\large (\color{red}a \ , \ \color{green}b)\) which the line passes through, then the equation of the line is given by \[\Large y = \color{blue}m (x-\color{red}a)+\color{green}b\]
Savvy? XD
:D
@terenzreignz :D
^_^ may pagkataray si uri
can anyone tell me the answer or how to solve the question????
I am... you know the slope m = -2 right? Now, what's a point that your line passes through... you're given two of them, we only need one, pick one ^_^
@terenzreignz would it be this one?? --->-y = 2x - 2
I don't know @ttop0816 let's find out. Now, pick one of your points...
terence what formula is this....havent used it ever.
is this same as y-y1=m(x-x1)?
@terenzreignz @uri im sorry but could i just get the answer this one time please? im in a hurry right now;
@uri's decision...
First tell me..Is the formula right? @terenzreignz
Of course @uri It comes from the point slope form \[\Large y-b = m(x-a)\]or if you like \[\Large y - y_0 = m(x-x_0)\] I just brought the b-over to the right side.
Why did you write y0 it's y1
Doesn't really matter :)
but aren't you confusing this kid? Because at schoool we usually use y-y1=m(x-x1) @terenzreignz
Yes, we use that, but if you notice, it looks NOTHING like her choices.
I adapt to the one that will most easily be recognisable.
Oh..so help her out in this one..@terenzreignz
I'm willing. But... work with me here @ttop0816 Come on, I'm just asking you (for now) to pick one of your two points...
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