if i was asked to compound something daily. what would I do?
use the compounding formula, with n=365 \[\Large P=A \left( 1+\frac{ r }{ n } \right)^{nt}\]
I did. Haley has deposited $816 in a savings account that earns interest at a rate of 2.9% compounded daily. What will the account balance be in nine years? that is the question. I put \[a=816(1+.029/365) ^(365*9)\]
But I got something really weird that wasn't even close to an answer
816*(1+.029/365)^(365∗9)
try that?
That is what I tried.
try entering it verrrrry carefully on your calculator, lol. I got an error the first time I did it, maybe had a paren in the wrong place or something. But then it worked and gave me the right answer.
Can also go here to evaluate: http://www.wolframalpha.com/input/?i=816%281%2B.029%2F365%29^%28365%E2%88%979%29 (It's already there for you.)
But your method appears to be correct.
\[a=816(1+.029/365)3285\]
when i do .029/365 i keep geting 7. something then an e with a -5..
yes, that's scientific notation, because 0.29/365 is a teeny, tiny number. :) I thought you were entering the whole expression in one entry, but you can do it one step at a time if you want, again, just be careful about the order and use of parens.
I always say, you can use too few parens but never too many! :)
Thank you so much!
You're welcome :)
Can you help me with something similar? What if I was asked compounded twice a year? That one I don't understand how to set up.
Set up the same, but only 2 compounding periods per year, so n=2.
n=# times compounded per year. So daily means 365, twice a year means 2, monthly would mean 12, etc.
Roberta deposited $4,790.23 into a savings account with an interest rate of 3.8% compounded twice a year. About how long will it take for the account to be worth $9,000? so i would set this up like \[a=4790.23(1+.038/2)^2 \]
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