solve for h, S=2pir^2+2pir^1h
wanna help me on this one too please?:) @gypsy1274
If only I could....what is pir?
\(S=2\pi r^2+2\pi r^1h\)
yes thats it
If the question read \(S=x+yh\) could you solve that for h?
yes you would subtract x then divide by y to get \[h=\frac{ -x }{ y } \frac{ s }{ y }\]
Almost. You would subtract x to get \(S-x=hy\) then divide by y to get \(\dfrac{S-x}{y}=h\). You could separate the fractions, but I seen no need for that.
okay so now back to my question cause that one didnt involve all these exponents and pi. i know the technique but some im just so lost
It is exactly the same thing. First subtract the term that does not include h.
Then divide by everything but the h in the term that does have h. This one cannot be simplified any further.
so it would be h=\[\frac{ s-2 \pi r ^{2} }{ 2 \pi r ^{1} }\]
Yes.
wow i feel so dumb it all makes sense now thanks again :)
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