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OpenStudy (anonymous):
wanna help me on this one too please?:) @gypsy1274
OpenStudy (anonymous):
If only I could....what is pir?
OpenStudy (anonymous):
\(S=2\pi r^2+2\pi r^1h\)
OpenStudy (anonymous):
yes thats it
OpenStudy (anonymous):
If the question read \(S=x+yh\) could you solve that for h?
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OpenStudy (anonymous):
yes you would subtract x then divide by y to get \[h=\frac{ -x }{ y } \frac{ s }{ y }\]
OpenStudy (anonymous):
Almost. You would subtract x to get \(S-x=hy\) then divide by y to get \(\dfrac{S-x}{y}=h\). You could separate the fractions, but I seen no need for that.
OpenStudy (anonymous):
okay so now back to my question cause that one didnt involve all these exponents and pi. i know the technique but some im just so lost
OpenStudy (anonymous):
It is exactly the same thing. First subtract the term that does not include h.
OpenStudy (anonymous):
Then divide by everything but the h in the term that does have h. This one cannot be simplified any further.
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OpenStudy (anonymous):
so it would be h=\[\frac{ s-2 \pi r ^{2} }{ 2 \pi r ^{1} }\]
OpenStudy (anonymous):
Yes.
OpenStudy (anonymous):
wow i feel so dumb it all makes sense now thanks again :)