Question

HELP PLEASE!!!

Answer 1

\[\frac{ 2x+6 }{ (x+3)^2 }+\frac{ x }{ x+3 }\]

Answer 2

take LCM. and then try to solve it. the LCM will be (x+3)^2.

Answer 3

Do I multiply that with the numerator also?

Answer 4

it will be. ( (2x+6) + x(x+3) )/ x+3)^2. from here you can calculate easily

Answer 5

I don't understand I think I calculated wrong because I got 2x and I don't think its right.

Answer 6

Can you explain to me the steps, so maybe I might understand it?

Answer 7

do you know how i get above equation that i give i previous comment

Answer 8

Look at the numerator on the left side
2x + 6 = 2*(x+3)
and the denominator can be factored
(x+3)*(x+3)

Answer 9

yes @wolf1728 is also right you can take common 2 in 2x + 6 and then you can cut x+3 with denominator it will make the problem more easy.

Answer 10

gsRttN Sorry to just barge in like that but I thought another approach might help.

Answer 11

is it \[\frac{ 2x }{ x+3 }\]

Answer 12

or \[\frac{ x+2 }{ x+3 }\]

Answer 13

which one @wolf1728

Answer 14

Christine - at the moment we are just concerned with the fraction on the left which has been changed to
2*(x+3) / (x+3) * (x+3)
After cancelling that do you get?

Answer 15

I get \[\frac{ 2 }{ x+3 }\]

Answer 16

2/x+3

Answer 17

Correct !!!

Answer 18

yay! I add them together which equals \[\frac{ x+2 }{ x+3 }\]

Answer 19

x+2/x+3

Answer 20

And that is the final answer - very good :-)

Answer 21

THANK YOU!!!! your medal will be with you shortly!! ^-^

Answer 22

Okay, thanks Christine and it's good to see you learned a little more about fractions.