Ask your own question, for FREE!
Physics 10 Online
OpenStudy (anonymous):

A ball is thrown vertically upward from the ground with an initial velocity of 20ft/sec. Need help here in determining the equations. o.o

OpenStudy (anonymous):

what are you from this given data?

OpenStudy (anonymous):

what do you mean? o.o

OpenStudy (anonymous):

What does the question exactly want?

OpenStudy (anonymous):

well, it asks for the equation for the length of the time the ball will be going up and maximum height of the ball can reach. Then we need to solve for those.

OpenStudy (anonymous):

just the equation because we will use derivatives to solve it.

OpenStudy (anonymous):

\[K = \frac{ 1 }{ 2 } mV ^{2}\]

OpenStudy (anonymous):

K = Energy m = Mass V = speed

OpenStudy (anonymous):

was there any constants included? o.o

OpenStudy (anonymous):

\[U = mgh\] U = Energy

OpenStudy (anonymous):

m=mass h=high

OpenStudy (anonymous):

I think you can use these equations to solve th question...

OpenStudy (anonymous):

Now give me a question like this...

OpenStudy (anonymous):

in this question initial velocity is only data,by using this initial velocity which means time T=0 this is only idea i got from the question

OpenStudy (anonymous):

yes!the question has to give us the energy and mass too.

OpenStudy (anonymous):

but it didn't gave anything else..

OpenStudy (anonymous):

please clearly say what i find from the question

OpenStudy (anonymous):

@Ryuusei , I will give you a question like this...wait...

OpenStudy (anonymous):

It is a easy question...let me write it...

OpenStudy (anonymous):

mass= 200gr V = 72Km/h K=?Kj

OpenStudy (anonymous):

solve

OpenStudy (anonymous):

what is k

OpenStudy (anonymous):

K is Energy

OpenStudy (anonymous):

what type of energy like potential,kinetic or some think else

OpenStudy (anonymous):

Kinetic Energy

OpenStudy (anonymous):

http://en.wikipedia.org/wiki/Kinetic_energy

OpenStudy (anonymous):

look

OpenStudy (anonymous):

1/2 mv2

OpenStudy (anonymous):

yes!but Ryuusei sholud find the answer...

OpenStudy (anonymous):

what can you find out from this question ? but our aim to determining qeuation

OpenStudy (anonymous):

sorry equation

OpenStudy (anonymous):

This question is the easier form of that question...OK?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

I keep on thinking.. but there's this answer that has 32t in it. I dunno why. This is from our teacher, but I don't know how he get it. v = 32t + 20. dunno with the signs, though. My copy is very blurry.

OpenStudy (anonymous):

that's why, I'm just asking for an equation.. o.o I already have the answers, but there's no solution. This is just like a practice, but I can't seem to trace it.

OpenStudy (anonymous):

nice question i will try to give answer

OpenStudy (anonymous):

this is the formula for a motion along a straight line final velocity =initial velocity+acceleration*time\[v=u+at\]

OpenStudy (anonymous):

cool.

OpenStudy (anonymous):

are you have any doubt

OpenStudy (anonymous):

no I don't have any doubts. I'm clearly accepting opinions. o.o

OpenStudy (anonymous):

but i have a doubt what is option 0.0

OpenStudy (anonymous):

@diwa , It's a nice formula!!Thank you!It's easier than 1/2mv2 and mgh...

OpenStudy (anonymous):

the answers says v(t) and s(t). v(t) falls into that one.. I dunno about s(t)

OpenStudy (anonymous):

s(t) is the displacement of the body

OpenStudy (anonymous):

okay.. I'll try to do this v(t).. but there isn't any.. acceleration given. ._.

OpenStudy (anonymous):

if there is any displacement

OpenStudy (anonymous):

or velocity

OpenStudy (anonymous):

it's just intial velocity = 20 ft/sec.

OpenStudy (anonymous):

ok have you only answer or solvation steps

OpenStudy (anonymous):

I'm almost there. I just don't know where this example got the 32t.. @_@

OpenStudy (anonymous):

ok ok thank you

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!