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Mathematics 15 Online
OpenStudy (anonymous):

How do you find the limit of f(x) as x approaches 3 from the left?

OpenStudy (loser66):

f(x)=??

OpenStudy (anonymous):

It doesn't give what it is I dont think but there is a graph

OpenStudy (anonymous):

OpenStudy (loser66):

what do you think?

OpenStudy (anonymous):

I m not sure even where to start. My textbook is confusing me more...

OpenStudy (loser66):

confirm: from your post, the point is 3. from your attachment, the point is 2. which one is the real problem?

OpenStudy (anonymous):

o sorry its 2.. mistype

OpenStudy (loser66):

I think it is = 3

OpenStudy (anonymous):

Ok Thanx :)

OpenStudy (loser66):

yw

OpenStudy (ybarrap):

$$ \large\text{If }\lim_{\tt{x}\to2^-}x=\lim_{\tt{x}\to2^+}x\text{ then } \lim_{\tt{x}\to2}x\text{ exists}\\ \large\text{From your chart we see that }\\ \large\lim_{\tt{x}\to2^-}x=\color{red}{\tt\bf{3}} \text{ and } \large\lim_{\tt{x}\to2^+}x=\color{red}{\tt\bf{-2}}\\ $$ Left and right limits at 2 are NOT equal.

OpenStudy (loser66):

@ybarrap but the question just ask about the limit of f(x) when x approaches to 2\(^{-}\),

OpenStudy (ybarrap):

The limit as x approaches 2 from the right is -2. The limit as x approaches 2 from the left is 3. These two limits are not equal so the limit at x=2 does not exist.

OpenStudy (loser66):

hey, as you say, "limit as x approaches 2 from the left is 3". That's the goal of the question, right? If they ask " what is the limit of f (x) when x approaches 2" then, your argument is valid.

OpenStudy (ybarrap):

You are right! I missed that part. Answer is 3.

OpenStudy (loser66):

hehehe.. thank you

OpenStudy (ybarrap):

I was just reading the word document, which has a different question.

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