A golf ball is hit from the ground with an initial velocity of 208 feet per second. Assume the starting height of the ball is 0 feet. How long will it take the golf ball to hit the ground? 13 secs 21 secs 42 secs 6 secs
Do you know the formula to use for this? There \(is\) a formula.
If you know that acceleration is change in velocity over change in time, then integration gives that acceleration time time is velocity. Solve for time. You're done!
That's a start, but I don't think you need calculus for this problem.
\(\bf \textit{initial velocity } \implies \large h = -16t^2+v_ot+h_o\\ -16t^2 = \textit{acceleration of object due to gravity, in English units}\\ h = \textit{height of object after "t" seconds}\\ v_o = \textit{initial velocity of launch}\\ h_o = \textit{initial height of object when launched}\)
woah wait what...?
Don't you need to know the direction of the original velocity of the ball too?
i just need to know how long it will take for the ball to hit the ground.
so, how are you supposed to get it without the "initial velocity" formula?
Ms Cleo got busted for phony advertising with a fake jamaican accent, so she can't help you there
Different initial directions affect the path of the ball. If the ball is hit horizontally, it will always be on the ground. |dw:1377457332328:dw|
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