Question

find domain: y=x-6/x^2-5x-36

Answer 1

First what you need to do is factor the numerator and denominator.

Answer 2

how?

Answer 3

To see if they have any common factors :P

Answer 4

\[y=\frac{x-6}{x^2-5x-36}=\frac{x-6}{(x-9)(x+4)}\]
Any value of \(x\) would work, except for those that make the denominator 0.

Answer 5

yea um just hopping in this lesson can u teach me like by steps

Answer 6

ok got it so the domain would be 9 and -4?

Answer 7

sorry x would not be 9 or -4

Answer 8

Yes. So you would say something like "all real numbers \(x\) except for 9 and -4."

Answer 9

ok thanks. so what if the problem has a radical in it like √3x-10/ Is the answer x is > or = 10/3?

Answer 10

SithsAndGiggles? Still There?

Answer 11

If \(f(x)=\sqrt{3x-10}\), then for \(f\) to be defined, you have the restriction that \(3x-10\ge0\), or \(x\ge\dfrac{10}{3}\). This would then be your domain, so yes you're right.