find the domain y = x^2-16/x^3+2x^2-9x-18. still not understanding how to do this
The denominator is \(x^3+2x^2-9x-18\), right?
What methods have you been taught for finding roots of a 3rd degree polynomial? Graphing? Rational root theorem? Synthetic division?
The problem is x^2 over x^3+2x^2-9x-18. Looking for the domain.
sorry the first part is x^2-16 over the rest
Ok, so like I said - the denominator of the function is \(x^3+2x^2-9x-18\). I just wanted to confirm that since you did not use any ( ) so it can be vague in meaning.
OK, the numerator isn't really very relevant if we are just looking for the domain. How do you find the domain of a rational function? Or maybe the way to ask it is: what kind of value ISN'T in the domain of a rational function?
E.g., for the function \(\Large y=\dfrac{ 3 }{ x-2 }\) ..... what is the domain?
2
The domain is 2?
No.... not exactly.....
everything except 2
RIGHT. So in general, how do you find the domain of a rational function? It's everything EXCEPT the values that............?
equal 0
Well, sort of. It's everything except the X values that make the DENOMINATOR =0. right? Remember - domain is all about the x's. What x's are ALLOWED to be plugged into the equation. When it comes to a rational function, the x's that are NOT allowed are those that make the den'r=0.
So what you need to do here, if find all the x's that make this den'r=0. That is, you have to solve: \(\Large x^3+2x^2-9x-18=0\) Which brings me back to.... :) What methods have you been taught for finding roots of a 3rd degree polynomial? Graphing? Rational root theorem? Synthetic division?
When you solve that equation, you'll know what has to be left out of the domain.
rational root
OK. so by rational root theorem, any rational root of this function (if one exists) must be a factor of what number?
2
That rational root theorem says that IF a number is rational root, then it is of the form \(\pm\)p/q, where p is a factor of the constant term (in this case, that is 18) and q is a factor of the leading coefficient (in this case, 1). so you need to find all factors of p=18, and q=1, (so in this case, really just all factors of 18). THAT list includes any rational roots. Notice that it doesn't guarantee that there are ANY rational roots - but only that, if there ARE, they are on that list.
ok so i got a domain of everything except for 3,-3 and -2
Very good - that's it! :)
Thank you
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