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Mathematics 22 Online
OpenStudy (anonymous):

Use graphs and tables to find the limit and identify any vertical asymptotes of the function.

OpenStudy (anonymous):

\[\lim_{x \rightarrow 2}1/(x-2)^2\]

OpenStudy (anonymous):

@Mertsj

OpenStudy (luigi0210):

btw Welcome to Openstudy :) @aaaaalicia

OpenStudy (mertsj):

Satellite is great at these questions and I see you lucked out...he is present.

OpenStudy (anonymous):

@Luigi0210 aww thank you :DD and @Mertsj okay cool beans!! i'll tag em up, thanks :)

OpenStudy (anonymous):

@satellite73

OpenStudy (luigi0210):

I can try to help :3 Do you know how to start this off?

OpenStudy (anonymous):

Yay!! okey @Luigi0210 um no I've no clue :)

OpenStudy (luigi0210):

I think it would help if we drew a graph. What is this btw? Calc I?

OpenStudy (anonymous):

precal :) and okay!

OpenStudy (anonymous):

the denominator goes to zero right? and it is always positive whereas the numerator is always 1

OpenStudy (luigi0210):

Oh, so you guys don't take infinity as an answer huh?

OpenStudy (anonymous):

so it goes up to infinity you can also view this as basically the same as \(\frac{1}{x^2}\) only shifted to the right 2 units

OpenStudy (luigi0210):

Btw, here is a visual:

OpenStudy (anonymous):

since it says "use a graph" look here http://www.wolframalpha.com/input/?i=1%2F%28x-2%29^2

OpenStudy (anonymous):

I see the graph but Im not really sure how to use that to explain what the v asymptotes are? I'm still not quite sure what they are! @Luigi0210 @satellite73

OpenStudy (luigi0210):

Well there is a vertical asymptote at x=2, because as the graph gets higher on the y axis they approach but never touch 2

OpenStudy (luigi0210):

I think there might be a horizontal asym. too, I'm not sure

OpenStudy (anonymous):

so the only vertical asym. of this is x=2?? and for that reason? omg this is confusing a little bit @Luigi0210

OpenStudy (luigi0210):

Yes, vertical at x=2 and horizontal at y=0. Sorry I'm awful at explaining >.<

OpenStudy (anonymous):

it's okay you were a good teacher :) @Luigi0210

OpenStudy (luigi0210):

I hope I didn't confuse you too much :)

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