Question

find the zeros : f(t)=175t-t^2

Answer 1

do you know what the difference of two squares is?

Answer 2

Hello @MCath Welcome to Openstudy :)

Answer 3

Helllloooooo
175 is 13.228????

Answer 4

this is not the difference of two square
factor as
\[f(t)=t(175-t)\] and then it should be straight forward

Answer 5

oh ok, just to clarify @satellite73 , when is it DOTS?

Answer 6

Yup, now just set each equal to 0 and solve :)

Answer 7

@seesawn When it has perfect squares:
Like (x^2-16)
or (x^2-25)
Or (4x^2-81)

Answer 8

@seesawn when it is
\[a^2-b^2\]

Answer 9

oh, thanks

Answer 10

how am i going to solve this

Answer 11

sorry i have no idea about this one T_T

Answer 12

@MCath, after you factor it to
t(175-t)
t=0 and 175-t=0

Solve
175-t=0 for t

Answer 13

175 isn't a perfect square how am i going to do with that
???

Answer 14

This problem doesn't require using perfect square. You just need to factor it and then solve for the zeros.

Answer 15

ohhhhhhhh
so {0,175} ??

Answer 16

Here's an example,

\[x^2-74x\]

x(x-74)
x=0 x=74

Answer 17

right
not to repeat myself, but this is NOT the difference of two squares
no idea where that came from

Answer 18

@MCath , are you sure your sign is correct for 175?

Show me your work

Answer 19

aahhhhh i really got no idea about this one.. but is this correct..

175t-t^2
t(t-175)
x=0 x=175????

Answer 20

hello

Answer 21

hello anybody there??

Answer 22

1. Set 175t-t^2 = to 0
2. Factor out t
3. Set each factor equal to 0
4. Solve each equation.

Answer 23

@MCath , you're right!

Answer 24

Yehey!! i have another question... please..
y=36x^2+36x+9 am i going to square all the numbers?? and after after squaring??

Answer 25

after squaring what will i do

Answer 26

What are you supposed to do with this problem?

Answer 27

FIND the zeros

Answer 28

Factor and set it equal to 0.
Set each factor equal to 0.
Solve each equation.
You will find that there is 1 double root since the given trinomial is a trinomial square.

Answer 29

ohhhh okay thanks so (6x+3),(6x+3) zeros are {-3,-3}
????? am i right??

Answer 30

no. Did you set each factor equal to 0 and solve?

Answer 31

\[6x+3=0\]
\[6x=-3\]
\[x=\frac{-1}{2}\]

Answer 32

ohhhhhhh

Answer 33

so the answer is
{-1/2,-1/2} ??

Answer 34

It is a double root. It would not be listed twice in the solution set.

Answer 35

The double root indicates a point of tangency to the x axis.

Answer 36

ohhhh okaaayyy thank you

Answer 37

yw