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Solve e^(-0.2x)=4
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Solve from x
*for
Use the natural log to get rid of the e, remember what you do to one side you must do to the other. Can you show me your work?
e^(-0.2x)=4 -0.2x=ln4 x=ln4/-0.2 x=-6.93 My math book is giving me a different answer
That is the answer that I get too
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lot of that going around tonight
Oh well....I'll just hope for the best :)
I figured out why the book gave me a different number. Apparently, fractions with something like 0.2 in the denominator are a "no no" in math problems like these. When I had x=ln4/.2 I should have realized the problem was saying.... \[\frac{ \ln 4 }{ 1} \div \frac{-1}{5}\] because .2=1/5. If you solve this, you get -5 ln4
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