Question

4-(6x^2-2)/(15)=(5x^2)/(3) - (5(x^2-2))/2

Answer 1

do you know answer of this?

Answer 2

@L-Lawliet-L

Answer 3

No.

Answer 4

If I would, i would not have asked it.

Answer 5

ok , then try to solve it. take LCM on both sides.

Answer 6

\[\frac{ 5x ^{2} }{ 3 }-\frac{ 5x^2-10 }{ 2 }\]

Answer 7

\[\frac{ 10x^2 }{ 6 }-\frac{ 15x^2-30 }{6 }\]

Answer 8

LCM on RHS will be 6

Answer 9

\[\frac{ 10x^2-15x^2-30 }{6}\]

Answer 10

the equation that you write is divide by 6 and also its not -30 , it will be +30

Answer 11

solve it. after solving LHS part take to RHS.

Answer 12

\[4-\frac{ 6x^2-2 }{ 15 }=\frac{ -5x^2+30 }{ 6 }\]

Answer 13

yes, you are right up to this step.

Answer 14

now take LCM on LHS first

Answer 15

\[\frac{ 60 }{ 15 }-\frac{ 6x^2-2 }{ 15 }=\frac{ -5x^2+30 }{ 6 }\]

Answer 16

solve it and then cross multiply it.

Answer 17

\[\frac{ 60 }{ 15 }-\frac{ 6x^2-2 }{ 15 }-(\frac{ -5+30 }{ 6 })\]

Answer 18

now you are doing wrong. 15 is denominator of 60-6x^2+2 whole.

Answer 19

don't take RHS Part to LHS , you first cross multiply it. it will make it easy.

Answer 20

@L-Lawliet-L

Answer 21

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