Question

Which method is most convenient in solving the given system of equations? x+3y=62x−3y=3

Answer 1

x + 3y = 6
2x - 3y = 3

Answer 2

@jlovely2,

would elimination method or substitution method work best here?

Answer 3

Yeah I would say substitution too. Solving the first equation for x in terms of y and z yields, x=3y-2z-12. Substituting the value of x in the second and third equations yields a system of two equations in two unknowns:

(3y-2z-12)+2y+3z=6
2(3y-2z-12)-3y-z=-2

=>

3y-2z-12+2y+3z=6
6y-4z-24-3y-z=-2

=>

5y+z=18
3y-5z=22

for z gives, z=-5y+18

substituting the value of z in the second equation gives:

3y-5(-5y+18)=22
3y+25y-90=22
28y=112
y=4

substituting the value of y in the first equation:

5(4)+z=18
20+z=18
z=-2

substituting the value of y and z in the value of x that we first got ^^ :

x=3y-2z-12
x=3(4)-2(-2)-12
x=12+4-12
x=4

The solution set is: { (4,-2,4) }

Answer 4

did i help u

Answer 5

@jonjenkins7653, you solved it good and well, but you used the wrong method and that wasn't what the question asked for.