Question

Solve (x + 2 < 5) U (x - 7 > -6).


{x | -6 < x < 5}
{x | x < 3 or x > 1}
Ø

Answer 1

a^2+2ab+c^2 .... so now here 2ab=2*5*1 and now link a which is 1 so be is 5 so add some to make 7 to 25 add 18 both sides then (x+5)^2 you will get (x+5)^2=18

Answer 2

U means or

x+2<5 or x-7>-6

x<3 or x>1

that is for all x in real numbers, the statement is true

Answer 3

The correct procedure for "completing the square" is as follows:
fir shift the constant to the other side
x^2 + 10x = -7
Now add the square of half of the coefficient of x to both sides
here coefficient of x is 10, its half is 5, so add 5^2 to both sides

x^2 + 10x + 5^2 = -7 + 5^2
Now LHS become (x+5)^2, so we can write
(x+5)^2 = -7 + 25
taking root of both sides
x+5 = +/-root(18)
x = -5 +/- 3root2
x = -5 + 3root2 or x = -5 - 3root2

Answer 4

completing the square not finding the value of x ??

Answer 5

the question said "solve by completing the square" so i guess we have to find values of x....

Answer 6

so B

Answer 7

@jonjenkins7653

Answer 8

yes