Question

https://world.cyberhigh.org/Courses/alg2b/unit6/images/qalg2b6d04q.gif

Answer 1

The equation for the nth term of a geometric sequence is
\[n ^{th}\ term=ar ^{n-1}\]
where a is the first term, and the common ratio is r.
So if
\[a _{n}=\frac{1}{4}\times6^{n-1}\]
can you identify the number that is equivalent to r ?

Answer 2

i dont get it

Answer 3

The general equation is
\[a _{n}=ar ^{n-1}\ .................(1)\]
So if
\[a _{n}=\frac{1}{4}6^{n-1}\ .............(2)\]
then the fraction 1/4 in equation (2) is equivalent to a in equation (1).
So in equation (2), is the number 6 eqivalent to r in equation (1)

Answer 4

So in equation (2), is the number 6 equivalent to r in equation (1)?

Answer 5

yes

Answer 6

did you already plug in the numbers

Answer 7

The numbers 1/4 and 6 are given in the question. So you have correctly found the answer, that r = 6.

Answer 8

o ok koo thanks

Answer 9

You're welcome :)

Answer 10

the way you wrote was kind of confused me

Answer 11

Sorry about that.