Question

Find an equation in standard form for the line described:

Passing through the points (1,4) and (-3,4)

If you could show the conversion from slope intercept to standard form in your work, that would help me understand this a lot!

Answer 1

can you get the slope off those 2 points?

Answer 2

Yeah, it's 0/-4

Answer 3

Which means that the line is horizontal?

Answer 4

yes

Answer 5

so our slope is 0, so let's use a point off those 2 available to us :)
let's say we use ( -3, 4)
and plug them in the slope-intercept form, gimme a sec

Answer 6

Alright... then what?

Answer 7

So basically it's 4=-3x0/4+b

Answer 8

\(\bf y-y_1=m(x-x_1)\quad \textit{using } (\color{red}{-3, 4}) \quad y-(\color{red}{4})=(0)(x-(\color{red}{-3}))\)

what do you get off that if you solve for "y"?

Answer 9

you get y=4?

Answer 10

as you can see, as you suspected, it's a horizontal line

Answer 11

So then how would this answer be converted into standard form? Or is y=4 already in standard form?

Answer 12

standard form? looks in order to me already
unless you mean y = mx+b so-called slope-intercept form

Answer 13

no no, I mean the Ax+By=C form

Answer 14

well, yes, y = 4 is standard polynomial form

you only have 1 variable, and 1 independent term, or so-called constant thus you could just rewrite it as y-4 = 0

Answer 15

http://www.mathsisfun.com/algebra/standard-form.html