Find the first few terms of the Maclaurin series for the following function:
secx=1/(cosx)
I know the series for cosx:
1-(x^2/2!)+(x^4/4!)-(x^6/6!)...+...
would i just take that series and 1 by that?

Question

Find the first few terms of the Maclaurin series for the following function:
secx=1/(cosx)
I know the series for cosx:
1-(x^2/2!)+(x^4/4!)-(x^6/6!)...+...
would i just take that series and 1 by that?

anonymous · Answer

divide by 1*

anonymous · Answer

Yes pretty much! That's the way it goes. If you see "cos(x)" anywhere in a expression, you can replace it with its series

anonymous · Answer

ok thanks!

dape · Answer

That would work perfectly fine, but sadly it isn't the Maclaurin series of sec(x). To get that you need to put 0 into sec(x) and it's derivatives, adding the terms together.

anonymous · Answer

hmmm..well for the series 1/cosx i got:

anonymous · Answer

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