Is the answer 1/4 ? The limit as x approaches pi/2 of (1-sinx) / (1+cos2x)
Is this your question: \[\lim_{x \rightarrow \frac{\pi}{2}}\frac{1-sinx}{1+\cos^2x}\]
Could also be \[\cos 2x\]
the bottom is 1+cos(2x)
Have you tried plugging in values?
I tried but it says to use l'Hopital's Rule so I did and I got 1/4 I'm not sure if its right though
Wouldn't it be -1/4?
Because the derivative of cos2x is -2sin2x
yeah and then i took the derivative again and got 4cos(pi) because when you plug in pi/2 you get 2pi/2 so the 2's cancel out don't they ?
When using L'hopitals don't we just take the derivative once?
No we can take it more than once if we have to. Well, at least that's what my teacher told us
No, it's actually just once.
It is ???
Wait, nevermind sorry, you were right
Sorry for wasting your time, but yea your answer is right :)
So is the answer 1/4 or -1/4
1/4
Okay thank you very much for your help :)
Yup :)
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