Question

I don't understand this formula:

Answer 1

E = h x f
(h -> Planck constant)

Answer 2

why?

Answer 3

which one that you dont understand?

Answer 4

\( \huge {E=hf=}\frac{ hc }{ \lambda }\)

Answer 5

The formula says, if you have a charged particle, and if that charged particle oscillates at a frequency f, then the energy that the electron would radiate will be in discrete packets of light, called the quanta, and each quanta would have a particular energy given by that relationship..

Answer 6

@deathgrowl , can you explain this formula more?
\[E = \frac{ hc }{ \lambda }\]

@Mashy , Thank you :)
can you give me a question?

Answer 7

what kind of question do you want?

Answer 8

I want a question about this formula

Answer 9

Ok..
if a light of frequency 10^16 Hz, is hitting a surface with a power of 10 watts, find the number of photons hitting that surface per second!

Answer 10

\( \large \bf {f=c/ \lambda }\)

Answer 11

@deathgrowl , what is \[\lambda \] here?

Answer 12

\( \large \bf{ \lambda}\) = wavelength :)

Answer 13

@Mashy :
\[E = hf => x = 10^{16} \times (6626068 \times 10^{-34})\]

Answer 14

but I think I made a mistake :(

Answer 15

@deathgrowl , Thank you :)

Answer 16

yea thats wrong :P

Answer 17

so please help

Answer 18

@Mashy , can you solve that question for me?

Answer 19

so you have \(\nu \) (frequency)= \(10^{16}\) Hz, units of Hz=1/s

E=\(h\nu\)=\((6.626*10^{-34}J*s)*(10^{16} /s)\)

and you have to know that 1 watt= 1 J/s

Answer 20

OH @aaronq ,Thank you very much :)
but I have another qustion,I think it seems VERY VERY VERY ... easy !
What is s in \( " (6.626 * 10 * s) " \)

Answer 21

6.626*10^-34 J*s is planck's constant (h)

Answer 22

No @aaronq , i don't know what is "s"

Answer 23

"s" is seconds

Answer 24

Thank you,You helped me very very good ;)

Answer 25

no probs dude!